(x+3)(x^3-5x+2)=0

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Solution for (x+3)(x^3-5x+2)=0 equation: 


Simplifying
(x + 3)(x3 + -5x + 2) = 0

Reorder the terms:
(3 + x)(x3 + -5x + 2) = 0

Reorder the terms:
(3 + x)(2 + -5x + x3) = 0

Multiply (3 + x) * (2 + -5x + x3)
(3(2 + -5x + x3) + x(2 + -5x + x3)) = 0
((2 * 3 + -5x * 3 + x3 * 3) + x(2 + -5x + x3)) = 0
((6 + -15x + 3x3) + x(2 + -5x + x3)) = 0
(6 + -15x + 3x3 + (2 * x + -5x * x + x3 * x)) = 0
(6 + -15x + 3x3 + (2x + -5x2 + x4)) = 0

Reorder the terms:
(6 + -15x + 2x + -5x2 + 3x3 + x4) = 0

Combine like terms: -15x + 2x = -13x
(6 + -13x + -5x2 + 3x3 + x4) = 0

Solving
6 + -13x + -5x2 + 3x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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